3 years ago

Find the domain of the rational function. f(x)= x+9/ x^2+ 16 ?

Mathematics

1 answer:

puteri [66]3 years ago

5 0

See attachment for answer:

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Vsevolod [243]

Answer:

$x < - \frac{5}{13}$

$x \geqslant - \frac{1}{5}$

Step-by-step explanation:

↷

$- \frac{13}{16}x + \frac{3}{8} < \frac{11}{16} \\ \frac{ \: \: \: \: \: \: \: \: \: \: \: \: - \frac{3}{8 } < - \frac{3}{8} }{ \frac{ - \frac{13}{16}x }{ - \frac{13}{16} } < \: \: \: \frac{ \frac { 5}{16} }{ - \frac{ 13}{16} } } \\ \\ x < \frac{ - 5}{ \: 13}$

↷

$\frac{1}{3} \geqslant \frac{2}{9} - \frac{5}{9} x \\ \frac{ - \frac{ 2}{9} \geqslant - \frac{2}{9} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{ \frac{ \: \: \: \frac{1}{9}x }{ - \frac{ 5}{9} } \geqslant \frac{ - \frac{5}{9} }{ - \frac{5}{9} } } \\ \\ x \geqslant - \frac{1}{5}$

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