Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

Thus, the starting and finishing time was 2:27 and 7:09 respectively.
Answer: I simplified it for you lol
Step-by-step explanation: Simplify the matrix.
19 + 266 inches
Answer:
19 Lollipops per friend
Step-by-step explanation:

F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer