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3 years ago

You bought a magazine for 4$ and 4 books you spent a total of 30$ how much did each book cost

Mathematics

2 answers:

pogonyaev3 years ago

3 0

Answer:

6.5

Step-by-step explanation:30-4=26

26 divided by 4 equals 6.5

iragen [17]3 years ago

3 0

Answer:

$6.50

Step-by-step explanation:

You have a total of 30 dollars

The given statement is that you spent $4 on a magazine, sense we already know this information then we can eliminate the given statement from the total

30-4=26

You have 26 dollars left and must be distributed among 4 books evenly

you must divide 26 by 4

26/4 = 6.5

Each book cost $6.50

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Select the correct answer. The graph of function f is shown. An exponential function passes through (minus 4, 9), (0, 1), (1, 0)

aksik [14]

The answer choice which correctly draws a comparison between the end behaviours of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.

<h3>Which answer choice correctly compares the end behaviour of the functions?</h3>

As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).

It therefore follows that as; x reduces (approaches -∞), the y value increases.

And, as x -increases (approaches +∞), the y-value decreases.

For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).

Consequently, as x reduces (approaches -∞), the y- values decrease.

And, as x increases (approaches +∞), the y-values decrease.

Ultimately, the two functions in discuss can be concluded to have; Choice C.

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1 year ago

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2 years ago

Convert 2000 Swiss francs to Dutch guilders

Shtirlitz [24]

Answer:

2000 swiss francs equals 3920 Dutch Guilders!

Step-by-step explanation:

One Swiss Franc equals 1.96 Dutch Guilders. Having said this, we can come up with the following equation:

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Where 'S' represents the swiss francs and 'D' the Dutch Guilders. Now, to convert 2000 Swiss francs, we just need to plug the value into the equation:

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3 years ago

Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition

vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) $\pi + (-\pi) = 0$

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

$1 - 2 = -1$

$5 - 5 = 0$

$\frac{1}{2} - \frac{1}{4} = \frac{1}{2}$

$4 - 2 = 2$

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

In the given options (a) to (d), only

$\pi + (-\pi) = 0$ is not close under addition because:

$\pi$ is irrational while $0$ is rational

<em>In other words, they belong to different set</em>

8 0

2 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

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