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We have given one irregular figure which is composed 2 triangle's and 3 rectangles
The height and base of the triangles is 6cm and 7 cm each
The length and breath of the rectangles is 13.1 cm and 7cm each

<h3>Let's Begin :-</h3>

We have, 

Therefore ,

We know that,

Area of triangle

$\bold{=}{\bold{\pink{\dfrac{1}{2}}}}{\bold{\pink{ × Base × Height }}}$

Subsitute the required values,

Area of 1 triangle 

$\sf{=}{\sf{\dfrac{1}{2}}}{\sf{ × 7 × 6 }}$

$\sf{ = 7 × 3 }$

$\sf{ = 21 cm²}$

<h3>Therefore, </h3>

Area of 2 triangle's

$\sf{ = 2 × ( Area\:of\:1\:traingle) }$

$\sf{ = 2 × 21 }$

$\sf{ = 42 cm² }$

Thus, The area of 2 triangles is 42 cm²

We know that,

Area of rectangle

$\bold{\red{ = Length × Breath }}$

Subsitute the required values,

Area of 1 rectangle

$\sf{ = 13.1 × 7 }$

$\sf{ = 91.7 cm² }$

<h3>Therefore,</h3>

Area of 3 rectangles

$\sf{ = 3 ×( Area\:of\:1\:rectangle) }$

$\sf{ = 3 × 91.7 }$

$\sf{ = 275.1 cm² }$

Thus, The area of 3 rectangle is 275.1 cm²

Total area of the given figure

$\sf{ = 42 + 275.1 }$

$\bold{ = 317.1 cm²}$

Hence, The total surface area of the given figure is 317.1 cm² .

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3 years ago