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Marta_Voda [28]
3 years ago
14

F(x)= 3x + 5

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Step-by-step explanation:

(3x+5)-(4x²-2)-(x²-3x+1)

= 3x+5-4x²+2-x²+3x-1

=6x+6-5x²

=-5x²+6x+6

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A machine that fills 12-quart size packages of ice cream runs 8 hours a day, 7 days a week. The machine fills 900 ice cream pack
otez555 [7]

Answer:

Number of ice cream packaged each week = 604,800 Ice cream

Step-by-step explanation:

Given:

One package = 12 ice cream

Per day packing = 8 hour

Number of days work in a week = 7 days

Per hour packing = 900 package

Find:

Number of ice cream packaged each week :

Computation:

⇒ Number of ice cream packaged each week = Number of days work in a week × Per day packing hour × Per hour packing × Per package ice cream

⇒ Number of ice cream packaged each week = 7 × 8 × 900 × 12

⇒ Number of ice cream packaged each week = 604,800 Ice cream

8 0
3 years ago
The temperature was -14°F
sleet_krkn [62]

Answer:

-21F

Step-by-step explanation:

You basically count 14+7 equal 21 so -14-7 is -21.

8 0
3 years ago
Read 2 more answers
There are 4 semi-trailer trucks parked in a line at the rest stop. After the first truck, each truck in the line weighs 2 tons m
butalik [34]
Let the weight of the first truck be represented by w.

total weight = w + (2 + w) + (2 + 2 + w) + (2 + 2 + 2 + w)
32 = 4w + 12
20 = 4w
w = 5

Therefore, the first truck weighs 5 tons, the second weighs 7 tons, the third weighs 9 tons and the fourth weighs 11 tons.
4 0
4 years ago
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Mai wants to make a scale drawing of her kitchen. Her kitchen is a rectangle with length 6 m and width 2 m. She decides on a sca
BigorU [14]

Answer:

Length of scale = 15 cm

Width of scale = 5 cm

Step-by-step explanation:

Dimensions of the kitchen of Mai are given as:

Length of kitchen = 6 m

Width of kitchen = 2 m

Scale to be used = 1 to 40

To find:

The drawing with labeling and dimensions of the scale drawing.

Solution:

First of all, let us understand about the concept of scaling.

Scaling is a method to represent big structures on paper.

For this purpose, we decide a scaling factor and draw the big structures on paper by scaling down (making it small) by using a scaling factor.

Here, the scale factor used is 1 to 40.

i.e. 1 unit on scale is equivalent to 40 units on the actual kitchen.

40 units of kitchen = 1 unit of scale

1 unit of kitchen = \frac{1}{40} units of scale

6 m of kitchen = \frac{1}{40}\times 6\ m = \frac{600}{40}\ cm = 15\ cm

Length of scale = <em>15 cm</em>

40 units of kitchen = 1 unit of scale

1 unit of kitchen = \frac{1}{40} units of scale

2 m of kitchen = \frac{1}{40}\times 2\ m = \frac{200}{40}\ cm = 5\ cm

Width of scale = <em>5 cm</em>

<em></em>

Please refer to the attached image as well for representation of given scale.

4 0
3 years ago
The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
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