Using the quotient rule
dy/dx = (x^-1) * (3x^2 -5 ) - (x^3 - 5x) * 2x
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(x^2 - 1)^2
You are correct
<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
Answer:
it is a because you subtract the ten from both side and that makes the -8 into a -18 then you divide by 3 and your answer is -6
