Answer:
a² + b² = c · (e + d) = c × c = c²
a² + b² = c²
Please see attachment
Step-by-step explanation:
Statement, Reason
ΔADC ~ ΔACB, Given
AC/AD = BA/AC, The ratio of corresponding sides of similar triangles
b/e = c/b
b² = c·e
ΔBDC ~ ΔBCA, Given
BC/BA = BD/BC, The ratio of corresponding sides of similar triangles
a/c = d/a
a² = c·d
a² + b² = c·e + c·d
a² + b² = c · (e + d)
e + d = c, Addition of segment
a² + b² = c × c = c²
Therefore, a² + b² = c²
The most direct form to graph a line, is to find two points of it and connect them with a line.
Here we have:
Let's find the point where x = 0. To do this, we replace the x in the equation by 0:
We have our first point: (0, -6)
Next let's find the point where y = 0. Again, we replace y in by 0 in the equation:
We have our second point, (3, 0)
Now all we have to do is plot the points (0, -6) and (3, 0) in the plane, and connect them with a line, and then the line is graphed
The line should look like this:
