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Yuki888 [10]
3 years ago
12

What is the measure . of ZBAC? ** (x + 10) с E (2x - 10) fo D

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

The measure of ∠BAC is 30°

Step-by-step explanation:

<h3><u>Given:</u></h3>

BAC = (x + 10)°

DAE = (2x - 10)°

Here, BAC and DAE are vertical angles, So they are equal

BAC = DAE

(x + 10)° = (2x - 10)°

x + 10° = 2x - 10°

Subtract 10° and 2x from both side we get,

x + 10° - 10° - 2x = 2x - 2x - 10° - 10°

-x = -20°

x = 20°

Here, The value of x is 20°

Now, We want to find ∠BAC

So,

∠BAC = (x + 10)° = 20° + 10° = 30°

Thus, The measure of ∠BAC is 30°

<u>-TheUnknownScientist</u><u> 72</u>

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Hope this helped :)

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3 years ago
Solve each equation by graphing the related function. if the equation has no real-number solution, write no solution. 3x^2=0
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3 years ago
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9.
marishachu [46]

Answer:

A. -4-3x>7

Step-by-step explanation:

-4-3(-5)>7

-4-(-15)>7

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3 0
3 years ago
the length of a rectangle is 3 cm more than twice its width. Find the largest possible width if the perimeter is at most 66cm
Vanyuwa [196]
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6 0
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Given the coordinates below, what is the midpoint of AB?<br> A(-6, -10)<br> B(2,5)
madreJ [45]

Given :

\:

  • A(-6, -10)
  • B( 2, 5)

\:

\gray{ \frak{The \:  given \:  two \:   \: points  \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}

\:

Let's solve by using midpoint formula :

\:

\bf \boxed{\color{red}\frak{Midpoint \:   \: Formula :  {( \: x ,\:y \:  ) = }(  \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}

\:

\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}

\:

\: \large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}

\:

\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{  \cancel\frac{ -4}{2} ,  \cancel\frac{ - 5}{2} )}}

\:  \:

\underline{ \boxed{ \large \red{ \frak{option \: d }(  \frak{   - 2, - 2.5)}}}}✓

Hope Helps! :)

6 0
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