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3 years ago

PLEASE HELP ASAP!!! WILL GIVE BRAINLIEST FOR BEST/RIGHT ANSWER!!!!!!!!

Mathematics

2 answers:

Nesterboy [21]3 years ago

7 0

The answer is A, please mark brainliest.

vladimir2022 [97]3 years ago

3 0

You're answer is A ☺

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Subtract 24 from 28 then divide by 2

Nookie1986 [14]

28-24=4/2=2
The answer is 2.

8 0

4 years ago

Drag each expression to show whether it can be used to find the area, perimeter, or neither

Blababa [14]

A = L * W
P = 2(L) + 2(W) or P = 2(L + W)

7 * 10 + 7 * 2 = 7(10 + 2) = 7 * 12.....this will get u the area
2 * 7 + 2 * 12 = 2(7 + 12) = 2(19)...this will get u the perimeter
7 + 12....this gets u neither
2(7 + 12).....this will get u perimeter
7 + 12 + 7 + 12......this will also get u perimeter
7 * 12....this will get u area

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> What is the value of x?

MA_775_DIABLO [31]

Answer: $\bold{C)\ -\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

$.\qquad \dfrac{x+2}{15}=\dfrac{x+1}{5}\\\\\\\rightarrow (15)\dfrac{x+2}{15}=\dfrac{x+1}{5}(15)\\\\\\\rightarrow x+2=3(x+1)\\\\\rightarrow x+2=3x+3\\\\\rightarrow \qquad 2=2x+3\\\\\rightarrow \qquad -1=2x\\\\\rightarrow \qquad -\dfrac{1}{2}=x$

8 0

3 years ago

Q3. Kylie sits two maths test. She scores 19/25 in the first one, and 16/20 in the second one.

Rina8888 [55]

She done better at the 2nd test because she only got 4 wrong but on the first test she got 6 wrong.

7 0

3 years ago

Read 2 more answers

One day, Karen bought 24 random cans of soup from a grocery store. Suppose that 7% of cans sold at that particular grocery store

MArishka [77]

Answer:

The probability that Karen has bought at least one dented can is 82.5%

Step-by-step explanation:

To know the probability of Karen buying at least one dented can, it's easier to calculate the probability of her not buying any dented can, and we know that:

$P_{\mbox{buying 24 cans}} =P_{\mbox{buying 24 non-dented cans}}+P_{\mbox{at least one dented can}}=1$

The probability of a can not being dented is (in the same principle as above, 100%(all cans)-7%(dented cans)=93%(non-dented cans) 0.93.

As the probability of a can being dented or not is independent from each other, we multiply the probabilities:

$P_{\mbox{buying 24 non-dented cans}}=0.93^{24}=0.175$

Now, we calculate the probability of at least one dented can, expressed as a percentage:

$P_{\mbox{at least one dented can}}= (1-P_{\mbox{buying 24 non-dented cans}})*100\\\\P_{\mbox{at least one dented can}}=(1-0.175)*100=82.5\%$

8 0

3 years ago