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aalyn [17]
3 years ago
10

Slow and steady wins the race. The leatherback sea turtle is the fastest known reptile, with a maximum speed of 21.9221.9221, po

int, 92 miles per hour (\text{mph})(mph)left parenthesis, start text, m, p, h, end text, right parenthesis.
Which of the following equations, where ddd is distance in miles and ttt is time in hours, represents a speed that is less than that of the leatherback sea turtle?
Choose all answers that apply:
Mathematics
1 answer:
Butoxors [25]3 years ago
3 0

Answer:lhlkkkkkkkkkkkww

Step-by-step explanation:

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30 m

Step-by-step explanation:

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Evaluate the expression 4+−4√2+−1√ and write the result in the form a+bi.
castortr0y [4]

In the expression, the real number a equals 12 and the real number b equals -16.

<h3>How to explain the information?</h3>

It should be noted that the expression given is:

= (4 - 2i)²

Therefore, we need to expand the expression. This will be:

= (4 - 2i)(4 - 2i)

= 16 -8i -8i + 4i²

= 16 -16i +4i²

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= 16 - 16i + 4(-1)

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Evaluate the expression ( 4 − 2 i )² and write the result in the form a + b i.

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lesantik [10]

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

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Necesitamos saber la respuesta a la ecuación, porque así es como funcionan las funciones.

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