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madreJ [45]
3 years ago
7

N=6x35+4 help please

Mathematics
1 answer:
wel3 years ago
4 0
6✖35:210
➕4:214
so that is the answer
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Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
Choose all of the following scenarios below that contain biased samples.
Korvikt [17]

Answer:

1 and 3 are biased

Step-by-step explanation:

A biased sample is ond where all individuals were not given equal likelihood of being selected.

Number 1;

Picking students from the cafeteria would lead to sampling bias because not every student from the school eats from the cafeteria. Those she selected can not be used to account for the whole school. Those that use the cafeteria are only a representation of the whole school and not the entire school.

For number 3:

Paul is interested in finding the mean number of cloth shoppers In a mall and is only collecting data from one clothing store without considering other stores in the mall.

7 0
2 years ago
Read 2 more answers
T3=-6.5 and t5=-3.9 determine d
nekit [7.7K]
t_3=-6.5;\ t_5=-3.9\\\\t_5-t_3=2d\\\\2d=-3.9-(-6.5)\\\\2d=-3.9+6.5\\\\2d=2.6\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{d=1.3}
4 0
3 years ago
Pls help will give brainiest
Anastaziya [24]

Answer:

2

Step-by-step explanation:

7 0
2 years ago
Solve for x<br> Logx-log(x+13)=1<br><br> Step by step explanation please
Lostsunrise [7]

Answer:

Step-by-step explanation:

Applying logarithm rule

Log A - Log B= Log(A/B). Division rule

Now, Logx-log(x+13)=1

Log(x/(x+13))=1

Assume that the log is a natural log whose base is 10.

Then apply logarithm law

Log10 base 10=1

Comparing this to Log(x/(x+13))=1

This implies that

x/(x+13)=10

x=10(x+13)

x=10x+130

x-10x=130

-9x=130

x=130/-9

x=-14.444

3 0
3 years ago
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