are those the options? something is wrong here and I'm not sure what. I'm sorry if this is wrong, I tried my best
Answer:
-2,928
Step-by-step explanation:
12 ( 32 - [ 23 • 12 ] )
order of operations PEMDAS ( parenthesis, exponents, multiplication/division, addition/subtraction )
23 • 12 = 276
12 ( 32 - 276 )
12 ( -244 )
-2,928
Answer:
The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2
The rule of arithmetic sequence = a + d(n - 1)
Where a is the first term and n is the number of terms
So, for the even numbers between 0 and X
The first term = a = 0
d = 2
So, we need to find n at the last term which is X
∴ X = 0 + 2 ( n -1 )
∴ n - 1 = X/2
∴ n = X/2 + 1
The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)
Substitute with a and d and X
So, the sum = (n/2) * (2*0 + (n−1)*2)
= (n/2) * ((n−1)*2)
= n(n-1)
= (X/2 + 1) * (X/2)
= X/2 by (X/2 + 1)
So, The quick way to add all even numbers between 0 and X always works.
Answer:
c
Step-by-step explanation:
-3x-2
-2x+11
+3x +3x
-2x+11
-11 -11
-13x
Answer:
Substitute n =1, 2, 3, 4, 5 to get the first five terms.
Step-by-step explanation:
(4). 
To find the first term, substitute n = 1.
Therefore, 
= 2
= 6
= 18
= 54
= 168
Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.
(5). 
= 4
Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.
