Hello here is a solution :
<span>x² − 8x − 4 = 0.
</span><span>quadratic equation ax²+bx+c = 0 when : a=1 and b= -8 and c = -4
discriminant : d = b²-4ac d= (-8)²-4(1)(-4) =64+16 =70
x= (-b-rot(d))/2a </span>x'= (-b+rot(d))/2a .......conrinu
Answer:
Step-by-step explanation:
Let v be the speed after the collision of both the cars.
Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get
⇒
⇒
⇒
Thus, they are moving at the velocity of
Answer:
xit the problem
Step-by-step explanation:
Answer: Choice A
y = -3(x+2)^2 + 10
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Work Shown:
y = -3x^2-12x-2 is in the form y = ax^2+bx+c with
a = -3
b = -12
c = -2
The x coordinate of the vertex is
h = -b/(2a)
h = -(-12)/(2*(-3))
h = 12/(-6)
h = -2
We'll plug this into the original equation to find the corresponding y coordinate of the vertex.
y = -3x^2-12x-2
y = -3(-2)^2-12(-2)-2
y = 10
So k = 10 is the y coordinate of the vertex.
Overall, the vertex is (h,k) = (-2,10)
Meaning that we go from this general vertex form
y = a(x-h)^2 + k
to this
y = -3(x - (-2))^2 + 10
y = -3(x+2)^2 + 10
