Solution:
Given: zj = 3- j2, zz = - 4 + j3
Part a:
zj = 3- j2 = 
zz = - 4 + j3 = 
Part b:
|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60
|z1| = √(3− j2)(3+ j2) = √
13 = 3.60.
Part c:
With the help of part a:
z1z2 = 
I think the answer is B Mean or median because there is no outlier.
<span>Divide by 3 get a remainder of 2
5, 8, 11, 14, 17, 20, ...
Divide by 5 get a remainder of 2
7 , 12, 17, 23, ...
Divide by 7 get a reminder of 5
12, 19, 26, 33, ...
And find a number in all three lists
</span>
<span>Not the most convenient way for sure, but since 47 works it will not take too long</span><span>
</span>
Answer:
60,120,180
Step-by-step explanation:
360:(2+4+6)=30
30×2=60
30×4=120
30×6=180
