Find 10x+y when x= 10 and y = 3. The answer is
1 answer:
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17. (a) The formula with CP subject is
(b) The Cost Price of item without GST is $59.50
(c) The GST of item is $5.95
Step-by-step explanation:
Given formula is;
SP = 1.1 * CP
SP = Selling price
CP = Cost price
(a) Rearrange the formula to make CP the subject;
SP = 1.1 * CP
Dividing both sides by 1.1
The formula with CP subject is
(b) Use your formula from (a) to find the Cost Price of an item without GST if the selling price is $65.45
SP = $65.45
The Cost Price of item without GST is $59.50
(c) Calculate the amount of GST on an item whose selling price is $65.45.
GST = 10% of CP
GST =
GST = 0.1CP
From part (b)
CP = $59.50
GST = 0.1 * 59.50
GST = $5.95
The GST of item is $5.95
Keywords: percentage, multiplication
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No, (2,2) is not solution of y < 4x - 6
Step-by-step explanation:
To solve above linear problem, we use standard method of Back- Substitution.
First of all, A point (2,2) only becomes solution of equation, if it satisfies equation .
Here, the seems to be like a linear equation.
In this Equation, using Back- Substitution method,
Point (2,2) : first digit 2 corresponds to x- coordinate and second digit 2 corresponds to y-coordinate.
By putting value of x and y in equation (1),
Equation becomes,
.... not true mathematically.
Finally, the result came is not true. Therefore, (2,2) is not solution for equation
Answer: p = 0.9337
Step-by-step explanation: from the question, we have that
total number of pen (n)= 15
number of pen that has never been used=9
number of pen that has been used = 15 - 9 =6
number of pen choosing on monday = 3
total number of pen choosing on tuesday=3
note that the total number of pen is constant (15) since he returned the pen back .
probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
probability of picking a pen that has been used on tuesday = 6/15 = 2/5
probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5
on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .
we know that
probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.
to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution
p(x=r) =
n= total number of pens=15
r = number of pen chosen on tuesday = 3
p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
by slotting in the parameters, we have that
p(x=3) =
p(x=3) = 455 *
p(x=3) = 455 * 0.064 * 0.002176
p(x=3) = 0.0633
thus probability that 3 of the pens has been used on tuesday. = 0.0633
probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337