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Tcecarenko [31]

2 years ago

5

Solve the following:

2 answers:

Montano1993 [528]2 years ago

8 0

Answer:

a) x=6

b) x=4.5

c) x=35

d) x=13

Step-by-step explanation:

german2 years ago

6 0

Answer:

a x = 6

b x = ⁹/²

c x = 35

d x = 13

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Step-by-step explanation:

Giving the following information:

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Help Q-Q 7/10c =4 1/5

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$\huge\mathfrak\green{answer}$

$= q - \frac{q7}{10} c = \frac{41}{5}$

$\red{multiply}$

$= q - \frac{cq7}{10} = \frac{41}{5}$

$\red{subtract \: q \: from \: both \: sides}$

$= q - \frac{cq7}{10} - q = \frac{41}{5} - q$

$\red{now \: simplify}$

$= - \frac{cq7}{10} = \frac{41}{5} - q$

$\red{multiply \: 10 \: both \: sides}$

$= 10( - \frac{cq7}{10} ) = 10. \frac{41}{5} - 10q$

$\red{simplify}$

$= - cq7 = 82 - 10q$

$\red{now \: divide}$

$= \frac{ - cq7}{ - q7} - \frac{82}{ - q7} - \frac{10q}{ - q7}$

$\red{simplify}$

$= c = - \frac{82 - 10q}{q7} (q≠0)$

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

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Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

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$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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