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adell [148]
3 years ago
14

Factorise k^2 + 5k + 6​

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer: (k+2) (k+3)

Step-by-step explanation:

Factor 5^2 +5k+6 using the AC method.

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Find the y intercept of the straight line with the following equations y=7+3x <br><br>3y=6x+12
neonofarm [45]

y = 7 + 3x

y = 3x + 7

y = mx + b, therefore the y-intercept is 7.


3y =  6x + 12

y = 2x + 4

y = mx + b, therefore the y-intercept is 4.

8 0
3 years ago
Can yall help me I want 3 problems done thank you if not can you at least do one?
Stells [14]

Answer:

1. the plants grew 50%

2. if the plants grew to be 8 inches instead of 9 the they would have grown 33% which is less than 50%

3. 100% increase

Step-by-step explanation:

See image for steps

7 0
2 years ago
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
Pls help. Will give brainliest
xenn [34]

Answer:1/2 and -7/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
read The question and give Me The answers for number 19 This is a Tough one it wants Me To click on The graph
shtirl [24]

Answer:

(0, 5)

Step-by-step explanation:

At the time the ball is thrown time t = 0

The corresponding height at t = 0 is 5 ft

This is the point (0, 5) on the graph

7 0
3 years ago
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