To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
You would hav to get 4% higher which Would get u to a c+
Answer:
x = 1
y = 4
Step-by-step explanation:
5x + 2y = 13
x + 2y = 9
Add both equations.
6x + 4y = 22
Solve for x.
6x = 22 - 4y
x = 22/6 - 4/6y
Put x as 22/6 - 4/6y in the second equation and solve for y.
22/6 - 4/6y + 2y = 9
-4/6y + 2y = 9 - 22/6
4/3y = 16/3
y = 16/3 × 3/4
y = 48/12
y = 4
Put y as 4 in the first equation and solve for x.
5x + 2(4) = 13
5x + 8 = 13
5x = 13 - 8
5x = 5
x = 5/5
x = 1
<span>Using: a^2 + b^2 = c^2 (pythagoras theorem)
where 'a' and 'b' are the legs of a right triangle, c is the hypotenuse
</span><span>compare the triangle I just drew to the triangle you have for your problem
</span><span>you'll see that a = unknown b = 18 c = 36
</span><span>a=18sqrt3
=31.2</span>
7x-(x-y) = 7x - x + y = 6x + y
9a-(2b-a) = 9a+a-2b = 10a-2b
hope it helped