Question

karl rode his bicycle 3/8 of the distance from Lakeview to bay cove,which is 24.1 miles. how many more does he need to ride to complete his trip ?

Answer 1

If 3/8 of the distance has been covered, there is a remaining of 5/8 of the distance to complete the trip. $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$

If 3/8 of the distance equals to 24.1 miles, to find the remaining 5/8:

24.1÷ 3 × 5 = 40.2 (rounded to the nearest decimal)

Answer 2

Answer:

Karl needs to ride 15.0625 miles more to complete his trip.

Step-by-step explanation:

There is a sketch attached to this answer.

If we divide the distance into eight equal parts, we can see graphically that Karl still needs to ride  $\frac{5}{8}$ of the distance.

In other words, we are dealing here with fractions. The total is 24.1mi (in terms of fractions the total is 1).

We can confirm this following the next steps:

• Karl needs to ride 24.1 miles from Lakeview to Bay Cove, that is, the distance from Lakeview to Bay Cove.

• We know that he rode $\\ \frac{3}{8}$ of the total distance, which is $\\ d_{rode}=\frac{3}{8}*24.1mi=9.0375mi$.

• But, he still needs to ride the rest of this total distance, that is: What is the rest of the total distance to ride?

• If we subtract what Karl has ridden to the total, we can determine the remaining distance in terms of fractions, that is: $\\ d_{left}=1-\frac{3}{8}=\frac{8}{8}-\frac{3}{8}=\frac{5}{8}$.

• In other words, Karl still needs to ride $\\ \frac{5}{8}$ of the total distance (as it was proposed at the beginning of this answer): $\\ d_{to-ride} = \frac{5}{8}*24.1mi$ or $\\ d_{to-ride} = 15.0625mi$

Then, Karl still needs to ride 15.0625 miles more to complete his trip.

We can check this result:

$\\ \frac{3}{8}+\frac{5}{8}=\frac{3+5}{8}=\frac{8}{8}=1.$

$\\ \frac{3}{8}*(24.1mi)=9.0375mi$

$\\ \frac{5}{8}*(24.1mi)=15.0625mi$

Which give us the total distance = 9.0375mi + 15.0625mi = 24.1mi.