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3 years ago

Is x greater than, less than, or equal to 110°?

Mathematics

2 answers:

artcher [175]3 years ago

8 0

Answer:

x is equal to 110°. ( being vertically opposite angles)

Svet_ta [14]3 years ago

7 0

Hey babes!

I’m certainly positive that x is equal to 110 degrees.

I hope this helps!

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Please help will give brainly onpicture

OLEGan [10]

I am not sure if it is A or B but it is definitely one of those because they have different y-intercepts. You have a 50/50 chance if you want to guess or you can graph it out and get an exact answer. Hope this helps!

5 0

3 years ago

Read 2 more answers

Leticia simplified an expression. Her work is shown below.

victus00 [196]

Leticia made a mistake in her step 2. She did subtraction before multiplication.

<h3 />

<h3>How to simplify an expression?</h3>

The expression can be simplified as follows;

4.5 ÷ 0.25 + 2.5 - 0.75 × 8

Hence, using Pemdas rule,

4.5 ÷ 0.25 + 2.5 - 0.75 × 8

18 + 2.5 - 0.75 × 8

18 + 2.5 - 6 = 14.5

Therefore, she made mistake in her step 2 because she was suppose to solve the multiplication before subtraction.

learn more on expression here: brainly.com/question/13545210

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4 0

2 years ago

Answers to 1-6 please :)

nikitadnepr [17]

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4 0

4 years ago

10 subtracted from the quotient of a number and -3 is at least -1

Mazyrski [523]

10 subtracted from the quotient of a number and -3 is at least -1 is:

$\left(\frac{x}{-3}\right)-10\ge \:-1\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-27\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-27]\end{bmatrix}$

Solution:

Given statement is:

10 subtracted from the quotient of a number and -3 is at least -1

Quotient means reuslt of dividing two numbers

Let the number be "x"

quotient of a number and -3 = $\frac{x}{-3}$

Therefore,

10 subtracted from $\frac{x}{-3}$ is at least -1

at least means "less than or equal to"

Which is translated into algebraic expression as:

$(\frac{x}{-3}) - 10\geq -1$

Solve the above inequality

$\left(\frac{x}{-3}\right)-10\ge \:-1\\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{x}{-3}-10+10\ge \:-1+10\\\\\mathrm{Simplify}\\\\\frac{x}{-3}\ge \:9\\\\Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

When we multiply or divide by negative number. we have to flip the inequality sign

$\frac{x\left(-1\right)}{-3}\le \:9\left(-1\right)\\\\\mathrm{Simplify}\\\\\frac{x}{3}\le \:-9\\\\\mathrm{Multiply\:both\:sides\:by\:}3\\\\\frac{3x}{3}\le \:3\left(-9\right)\\\\\mathrm{Simplify}\\\\x\le \:-27$