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IgorC [24]
3 years ago
15

A pie was cut into 8 equal slices. if Ruben ate 3/4 of the pie, how many slices did he eat?

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
6 slices 4 x2 = 8 and 3 x 2 = 6 so its 6 over  and that is 6/8 of the pie
Butoxors [25]3 years ago
8 0
He ate 6 slices. Think like a traditional pizza slice. It's usually cut in eighths. Divide by 2 to get 4/4. 2 slices is one fourth. 2,4,6.
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If 120% is £360 what is 100%
AleksAgata [21]
In this question a vital information has been provided. This information can be used for determining the answer to the question that is asked. It is given that 120% of a certain number is 360 pound. The 100% value of the number needs to be determined.
Let us assume the number to be = x
Then
120x/100 = 360
12x/10 = 360
12x = 360 * 10
12x = 3600
x = 3600/12
   = 300
 Now we can say that the 100% of the number or the actual number is 300 pounds. I hope the problem is clear to you and you can understand the trick involved in the question.
6 0
3 years ago
A linear function has a slope of 8/3 and passes through the point (0,5). What is the equation of the line?
MArishka [77]

This problem already gave us the slope and y-intercept, so all that's left to do is plug those two values into slope-intercept form.

Slope-Intercept Form: y = mx + b

---m is the slope

---b is the y-intercept

y = 8/3x + 5

Hope this helps!! :)

3 0
3 years ago
Read 2 more answers
Answer this question pls? Its 20 pts
ICE Princess25 [194]

Answer:

B   a = 180 -77-60

Step-by-step explanation:

The angles add to 180 degrees since they form a straight line

77+ 60+a = 180

a = 180 -77-60

6 0
3 years ago
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What is the common difference for the arithmetic sequence?
kramer
The common difference is -6.

Because,
14 - 6 = 8
 8 - 6 = 2
 2 - 6 = -4
 -4 - 6 =-10
5 0
3 years ago
Read 2 more answers
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
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