Question

Please help me with thissss

Answer 1

>> Answer

_________

• Number (A.)

$\sqrt{3} \times \sqrt{6} = ...$

$= \sqrt{3 \times 6}$

$= \sqrt{18}$

$= \sqrt{9} \sqrt{2}$

$= \bold{3 \sqrt{2}}$

.

• Number (B.)

$\sqrt{8} \times \sqrt{18} = ...$

$= \sqrt{8 \times 18}$

$= \sqrt{144} = \bold{12}$

Answer 2

Answer:

see explanation

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

(a)

$\sqrt{3}$ × $\sqrt{6}$

= $\sqrt{3(6)}$

= $\sqrt{18}$

= $\sqrt{9(2)}$

= $\sqrt{9}$ × $\sqrt{2}$

= 3$\sqrt{2}$

(b)

$\sqrt{8}$ × $\sqrt{18}$

= $\sqrt{8(18)}$

= $\sqrt{144}$

= 12