Answer:
Step-by-step explanation:
1) AC⊥BD and BD bisects AC 1) given
2) AD≅DC 2) linear bisector thm.
3) ∠ADB and ∠CDB are right angles 3) perpendicular bisector thm.
4) ∠ADB ≅ ∠CDB 4) all right ∡'s are congruent
5) BD ≅ BD 5) reflexive POV
6) ΔABD ≅ ΔCBD 6) SAS
Hope this helps!
btw, I was not able to put the lines on top of some of the letters, so my apologies.
4 packages, because 24/12=2, 8/2=4 packages.
let's plug in the value of y :
Answer:
216 cm²
Step-by-step explanation:
Applying,
V = lwh..................... Equation 1
Where V = volume of the cubiod, l = length of the base, width of the base, h = heigth of the cubiod.
From the question,
Since the base of the cubiod is squared,
Therefore,
w = l = 4 cm, V = 400 cm³
Substitute these values into equation 1
400 = 4×4×h
h = 400/(4×4)
h = 25 cm
A = lw+lh+wh.................. Equation 1
Where A = surface area of the cuboid.
Given: l = 4 cm. w = 4 cm, h = 25 cm
Substitute these values into equation 1
A = (4×4)+(4×25)+(4×25)
A = 16+100+100
A = 216 cm²
