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Y_Kistochka [10]
3 years ago
8

Simplify 455 degrees

Mathematics
1 answer:
stealth61 [152]3 years ago
8 0

Answer:

12

Step-by-step explanation:

(-455)-(-233)+(234)

-455+233+234

(233+234)-455

467-455

12(answer)

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Find the GCF of the numbers using lists of factors.<br> 27,45<br> 30,48<br> 28,48,64
Svetach [21]

Answer:

1.) 6

2.)6

3,)4

Step-by-step explanation:

I think these are the gcf of the numbers

6 0
3 years ago
What is the length of arc S shown below?<br> The angle in the figure is a central angle in radians.
Taya2010 [7]

Answer:

2

Step-by-step explanation:

Arc length = r × theta

Arc length = 5 × 0.4

= 2

3 0
3 years ago
If you apply the changes below to the linear parent function, Fx) = x, what is
Inga [223]

Answer: A. G(x)= ax=y= - f(x) is flip over x-axis. Therefore, f(x) =14x would become f(x) =-14x. Therefore, final transformed function f(x)=-14x is vertically stretch by a factor of 14 and flip over the x-axis.

5 0
3 years ago
Please help meeeee. I literally learned this last year but my dum mb self forgot hot to do it
Aleks [24]

It would be 30 because 10^4 is 10000 and 10000 times 12 is 120000 and 10^3 is 1000 and 1000 times 4 is 4000 so 120000 divided by 4000 is 30

8 0
3 years ago
If possible help me in this. I need to find the two odd numbers...​
Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer:  x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15  or  -15, -13</h3>
4 0
2 years ago
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