10!=10*9*8*7*6*5*4*3*2*1=3628800
The value of the required integral is 50π where C is the positively oriented circle x2+y2=25
We are given a vector F = -yi + xj. A vector is a quantity with magnitude and direction that is commonly represented by a directed line segment, with length representing magnitude and orientation in space representing direction. We need to use the tangential vector form of Green's Theorem to compute the circulation integral ∫CF⋅dr where C is the positively oriented circle x² + y² = 25
Let the value of the integral be represented by the variable "I".
I = ∫∫[(/x)(x) - (/y)(-y)]dA
I = ∫∫[(1 - (-1)]dA
I = ∫∫2dA
I = 2∫∫dA
I = 2×(Area of the circle)
I = 2*(πr²)
I = 2*(π*25)
I = 50π
Hence, the value of the required integral is 50π.
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Answer:
1g - 16
Step-by-step explanation:
-2 (3g - 8g +8) -9g
-2(-5g +8) - 9g
10g - 16 + -9g
1g - 16
Answer:
V = 90π in³
Step-by-step explanation:
Volume of cilinder
=Area of cicle that is the base * height of cylinder
V = π·r²·h
V = π·3²·10
V = π·9·10
V = π·90 in³
7 because 6 and 3/4 is written out as 6.75 and when rounding you look at the number after the decimal and if its 5 and above you round up the number youre about to estimate and if its 5 and below you round down.
