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3 years ago

Please answer this I don’t no how to do this.

Mathematics

2 answers:

sp2606 [1]3 years ago

4 0

Answer:

Hope this helps! :)

Step-by-step explanation:

Vedmedyk [2.9K]3 years ago

3 0

Answer:I think its( -1, 6)

Step-by-step explanation:and hi again

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Find the equation of the linear function represented by the table below in slope-intercept form.

Alex787 [66]

Answer:

Let's first find the slope.

-13 - (-8) / 2-1

-5/1

-5

The slope is -5.

The y intercept, or where the line crosses the y=axis, is equal to -3.

So, the equation is y=-5x-3

Let me know if this helps!

7 0

3 years ago

The first step in calculating the mean is to ____the numbers<br> add<br> group

Blababa [14]

The first step in calculating the mean is to add the numbers. After that you divide by the number of items in the data set. You don’t need to group the numbers to find the mean. Hope this helped!

4 0

4 years ago

Read 2 more answers

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

Need help

Cloud [144]

The answer should be B.

5 0

3 years ago

Which measure would be best to describe the typical travel distance of this friend group this year? Please submit the explanatio

allsm [11]

Answer:

Which measure of central tendency is usually the best way to describe a set of data?

Summary of when to use the mean, median and mode

Type of Variable Best measure of central tendency

Nominal Mode

Ordinal Median

Interval/Ratio (not skewed) Mean

Interval/Ratio (skewed) Median

Step-by-step explanation:

4 0

4 years ago