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3 years ago

I need help with long divson

Mathematics

1 answer:

beks73 [17]3 years ago

6 0

Answer:

53×3= 159

1908-159(0)= 318

53×6= 318

318-318=0

Answer- 36

first blank-

(1) 5 9

______

Second blank-

(3) 1 8

3 1 8

______

third blank-

0

_____

Answer-

3 6

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-5(x + 1) s 30. What is a possible value of x? help me pls

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Answer:

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Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs

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Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

$Length: 10\ in$

$Width: 8\ in$

Required

Determine the possible dimensions of Rectangle B

The question has missing options; however, the question can still be solved.

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

$Length: 15 in$

$Width: 12 in$

Divide the corresponding lengths of B by A to get the enlargement ratio

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{15}{10}$

$Ratio = 1.5$

For width

$Ratio = \frac{12}{8}$

$Ratio = 1.5$

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

$Length: 20\ in$

$Width: 10\ in$

Calculate Ratios

$Ratio = \frac{B}{A}$

For length:

$Ratio = \frac{20}{10}$

$Ratio = 2$

For width

$Ratio = \frac{10}{8}$

$Ratio = 1.25$

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy

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It is a rational number

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Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

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P is a letter and 23 is a number

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