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3 years ago

What is the sum of the first 27 terms of the following sequence?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

Answer choices............................

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Write an inequality to represent the situation. <br> A cheese pizza costs at least $5.

Nady [450]

<
- 5 dollars, the V thing sits on top of the line and 5 comes after signifying that it could be 5 dollars or more

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3 years ago

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Plz help out!! And no this is not a test :)

jolli1 [7]

9514 1404 393

Answer:

B = (-4, 5)

Step-by-step explanation:

Reflection over the origin changes the signs of the coordinates.

(x, y) ⇒ (-x, -y)

(4, -5) ⇒ (-4, 5)

Point B is (-4, 5).

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3 years ago

Read 2 more answers

Not very good at geometry

FromTheMoon [43]

It's B - 1/√3
because tan is opposite side over adjacent

6 0

3 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago

Pls help asap not very good @ math

yanalaym [24]

Answer:

b. The function is linear and has y intercept (0, 20,000)

Step-by-step explanation:

The function is linear and has y intercept at (0, 20,000)

8 0

3 years ago