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chubhunter [2.5K]
2 years ago
6

What is the domain of f?

Mathematics
1 answer:
KengaRu [80]2 years ago
5 0
For the whole thing including the other point it would be [-6, 6] but just for f it should be [6]
You might be interested in
If the length of one base of a trapezoid is 44, the median is 36, and the other base is 2x + 10, find x.
sergejj [24]

Answer:

  9

Step-by-step explanation:

The median is the average of the base lengths. Where "b" is the length of the other base, we have ...

  36 = (44 +b)/2

  b = 72 -44 = 28

We are told this is the same as 2x+10, so we have ...

  28 = 2x +10

  18 = 2x . . . . . subtract 10

  9 = x . . . . . . . divide by 2

The value of x is 9.

6 0
2 years ago
A bank branch located in a commercial district of a city has the business objective of improving the process for serving custome
choli [55]

Answer:

We conclude that the mean waiting time is more than or equal to 5 minutes at 5% level of significance.

Step-by-step explanation:

We are given that waiting time is defined as the time the customer enters the line until he or she reaches the teller window.  

A random sample of 15 customers is selected. Results found that the sample mean waiting time was 4.287 minutes with a sample standard deviation of 1.638 minutes.

Let \mu = <u><em>mean waiting time.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 5 minutes     {means that the mean waiting time is more than or equal to 5 minutes}

Alternate Hypothesis, H_A : \mu < 5 minutes      {means that the mean waiting time is less than 5 minutes}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                              T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 4.287 minutes

            s = sample standard deviation = 1.638 minutes

            n = sample of customers = 15

So, <u><em>the test statistics</em></u>  =  \frac{4.287 -5}{\frac{1.638}{\sqrt{15} } }  ~ t_1_4

                                       =  -1.686

The value of t test statistics is -1.686.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.686 > -1.761, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean waiting time is more than or equal to 5 minutes.

5 0
3 years ago
Cierra says that 5/6 times 5/6 equals 25/6 is that true?
Sholpan [36]

Answer:

No

Step-by-step explanation:

5/6 * 5/6 = .6944

25/6 = 4.1667

8 0
2 years ago
Suppose you have 60 red marbles and 40 blue marbles in a
andrew-mc [135]

Answer:  The required probability is 0.26.

Step-by-step explanation: Given that there are 60 red marbles and 40 blue marbles in a  box 10 marbles are picked without replacement.

We are to find the probability of selecting 6 red marbles.

Since the marbles are picked up without replacement, so it is a situation of combination.

Let S denote the sample space of the experiment of drawing 10 marbles and E denote the event that 6 marbles are red.

So,

n(S)=^{100}C_{10}=\dfrac{100!}{10!(100-10)!}=\dfrac{100!}{10!90!}=17310309456440,\\\\\\n(E)=^{60}C_6\times^{40}C_4=\dfrac{60!}{6!54!}\times\dfrac{40!}{4!36!}=50063860\times91390.

Therefore, the probability of event E is given by

P(E)=\dfrac{n(E)}{n(S)}=\dfrac{50063860\times91390}{17310309456440}=0.26.

Thus, the required probability is 0.26.

6 0
3 years ago
Match the right side of the equation to the left side<br> cot x sec^4 x=cot x+ 2 tan x+tan^3 x
Natalka [10]

Step-by-step explanation:

cot x + 2 tan x + tan³ x

Write in terms of sine and cosine:

(cos x / sin x) + 2 (sin x / cos x) + (sin³ x / cos³ x)

Find the common denominator:

(cos⁴ x / (sin x cos³ x) + 2 (sin² x cos² x / (sin x cos³ x)) + (sin⁴ x / (sin x cos³ x))

Add:

(cos⁴ x + 2 sin² x cos² x + sin⁴ x) / (sin x cos³ x)

Factor:

(sin² x + cos² x)² / (sin x cos³ x)

Pythagorean identity:

1 / (sin x cos³ x)

Multiply top and bottom by cos x:

cos x / (sin x cos⁴ x)

Simplify:

cot x sec⁴ x

5 0
3 years ago
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