28:24
14:12
7:6
The ratio is 7:6
Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Answer:
$5
Step-by-step explanation:
Because everyone want to be rich!
2.3 will be your answer
2 for the 2 (whole)
.3 is 3/10
if it was 3/100, it will be .03
hope this helps
Answer: 17,147
Step-by-step explanation:
