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Shalnov [3]
2 years ago
14

Helppppppp

Mathematics
1 answer:
Yakvenalex [24]2 years ago
6 0

Answer:

7 -if rounded to the nearest tenth would be 10

Step-by-step explanation:

The median is the number in the middle so

6-6-7-7-10-12-14

There are 7 numbers here so the middle number is 4 because there are 3 numbers before 4 and 3 numbers after 3 to get to 7 (that’s really hard to explain sorry but it’s a simple concept) my trick is to write it down then use two fingers to point at the first and last number and keep doing that moving in til I get to the middle number, which is 7. :)

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Stem of Equations<br> Substitute (2, 1) into x + 3y = 5 to get<br> =
algol [13]

Answer:

see below!!

Step-by-step explanation:

x + 3y = 5,

y = –x + 3

Substitute the point into each equation and verify that it is true

x + 3y = 5,  2 +3(1) = 5   5 = 5  true

y = -x +3    1 = -2+3     1=1  true

(2,1) is a solution

6 0
2 years ago
1)
VikaD [51]

Answer:

a. Point S

b. Line segment PT and Line segment ST

c. PSQRU

d. Lines PR and SQ

e. Plane C and Plane QRS

Step-by-step explanation:

7 0
2 years ago
The function y=-5x+2 is transformed by reflecting it over the y axis. What is the equation of the new function?
vampirchik [111]

y = mx + b

When a function is reflected over the y-axis, the b (2) stays the same but the slope (m) changes to its opposite sign.

since the slope is negative in this equation, it will become positive.

so the new fuction will be

y = 5x + 2

7 0
3 years ago
Find the value of this experssion x = -9<br><br> x - 3 x + 5?
aalyn [17]
If you are imposing the x=-9 then, the problem would be set up like this:
=-9-3(-9)+5
=-9-(-27)+5
=18+5
=23
8 0
3 years ago
Read 2 more answers
Which is the equation of an asymptote of the hyperbola whose equation is
goldfiish [28.3K]

Answer:

C. y = 3x - 5

Step-by-step explanation:

Given the general equation of a hyperbola:

\frac{(x-h)^{2} }{a^{2}}-\frac{(y-k)^{2} }{b^{2}}=1

The equation for the asymptote line is given by:

y=k+\frac{b}{a} (x-h)

In your problem, we have

\frac{(x-2)^{2} }{4}-\frac{(y-1)^{2} }{36}=1

we have:

h=2,

k=1

a²=4 --> a=2,    im just taking the squareroot

b²=36 --> b=6

put it into your equation

y=k+\frac{b}{a} (x-h)

y=1+\frac{6}{2} (x-2)

y = 1 + 3(x-2)

y = 1 + 3x - 6

y = 3x - 5

4 0
3 years ago
Read 2 more answers
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