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iren2701 [21]
3 years ago
12

Several ordered pairs from a continuous exponential function are shown in the table. what are the domain and range of function?

Mathematics
2 answers:
Elodia [21]3 years ago
7 0

Answer with Explanation:

The points when plotted on two dimensional plane, forms a continuous exponential function curve

x     0      1       2             3

y      4     5      6.25    7.8125

If you plot the points on the coordinate plane and try to find the exponential function,the function can be written as

 y=4 e^{\frac{x}{4.50}}

Domain of a function is defined as set of x values ,for which y is defined.

For,every real value of x , y is defined.

→Domain = Set of real numbers=(-∞,∞)

Range of a function is defined as set of y values ,for which x is defined.

e^{\frac{x}{4.50}=\frac{y}{4}}\\\ \frac{x}{4.5}=\log\frac{y}{4}\\\\ x=4.5\log\frac{y}{4}

Log of any function is defined for , positive real numbers that is numbers between 0 to ∞.

→Range =(0,∞).

So,→ domain of the function is Set of Real numbers and Range is y>0.

None of the option among four options is true.

son4ous [18]3 years ago
5 0

the answer is b......

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163%

Step-by-step explanation:

Find in-between 25 and 300, which is 162.5 ,round to the nearest percentage being 163%. Hence your answer

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Answer: She had 60% of the money left

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This table shows a proportional relationship between the variables x and y.

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3 years ago
The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg
amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

Step-by-step explanation:

From the question, we have the following information:

  • The distribution for protein requirement is <em>normally distributed</em>.
  • The population mean for protein requirement for adults is \\ \mu= 0.65 gP*kg^{-1}*d^{-1}
  • The population standard deviation is \\ \sigma =0.07 gP*kg^{-1}*d^{-1}

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than \\ x = 0.60 gP*kg^{-1}*d^{-1}.

For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

\\ z = \frac{x - \mu}{\sigma}

For the given parameters, we have:

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = -0.7142857

<h3>Determining the probability</h3>

With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.

Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

\\ P(x

\\ P(x (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0
3 years ago
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