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VladimirAG [237]
3 years ago
15

Find the equation of the line shown

Mathematics
2 answers:
Ymorist [56]3 years ago
7 0

Find the equation of the line shown in the picture.

Answer:

y = x + 6

anzhelika [568]3 years ago
3 0

Answer:

firstly you have to find the slope of the line.

Step-by-step explanation:

for thus, use the number which is on the coordinate system like x and y. the slope is (10-6)/(4-0) =1 so m=1

the equation should be on this form y-y1=m"(x-x1)

then put the value of y and x from equation.

when the x is 4 the y have to be 10

y-10=1*(x-4)

finally the equation is y=x+6

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PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

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Solve the exponential equation using the method of relating the bases by first rewriting the equation in the form of e^u=e^v
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