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3 years ago

Find the equation of the line shown

Mathematics

2 answers:

Ymorist [56]3 years ago

7 0

Find the equation of the line shown in the picture.

Answer:

y = x + 6

anzhelika [568]3 years ago

3 0

Answer:

firstly you have to find the slope of the line.

Step-by-step explanation:

for thus, use the number which is on the coordinate system like x and y. the slope is (10-6)/(4-0) =1 so m=1

the equation should be on this form y-y1=m"(x-x1)

then put the value of y and x from equation.

when the x is 4 the y have to be 10

y-10=1*(x-4)

finally the equation is y=x+6

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the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers

notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

$y = k * x$

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

$476 = k * 17$

From here, we clear the value of k:

$k = \frac{476}{17}\\k = 28$

Therefore, the relationship is:

$y = 28x$

For 1428 kilometers we have:

$1428 = 28x$

Clearing the amount of fuel we have:

$x = \frac{1428}{28}\\x = 51$

Answer:

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3 years ago

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Firdavs [7]

The answer is between 45,000,000-65,000,000

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4 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

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we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

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$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

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Step-by-step explanation:

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4 years ago

Read 2 more answers