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diamong [38]
2 years ago
5

Given that tan π/6 = 1/√3 and tan 3π/4 = -1. Express tan 7π/12 in the form of r + k√q, where k,r and q are integers. Hence, show

that tan 7π/6 = √q/3​
Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0
Dhdhhdjdhfhfjififf yo jo se
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Find the area of the shaded part of the triangle below. Round to the nearest tenth if needed.
konstantin123 [22]

Answer:

212.5

Step-by-step explanation:

For triangles, A = (bh)/2

You can do 15+25 to find the base, which is 40. From here do 17*40/2. You get 340. However, you need to remove the right triangle on the left side.

Again do 17*15/2, which you get 127.5.

From here subtract 127.5 from 340 and get 212.5

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3 years ago
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Solve this question
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You have to split it into triangles
but you have to know how to use pythagorus in 3D shapes

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A survey of 11 students showed that 8 liked science, 7 liked mathematics, and 4 liked both. How many students just liked science
andreyandreev [35.5K]

Answer:

4 I guess..........not sure but my answer is 4

5 0
3 years ago
Which one is it.<br>You can choose more than one.​
spayn [35]

Answer:

3 and 8

Step-by-step explanation:

6,240/3=2080

6,240/9=693.3333333.....

6,240/780

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3 years ago
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A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
2 years ago
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