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Ierofanga [76]
3 years ago
15

A.0.16, 0.10, 0.07, -2.65, -1.43

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

Step-by-step explanation:

The greatest value is 0.16. The least value is - 2.65

The least value (mathematically) is - 2.65

So C is the right answer.

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What is the missing pattern 7, 11, 2, 18, -7
Alexxx [7]

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

<h3>What is the missing element in a sequence?</h3>

A sequence is a set of elements which observes at least a <em>defined</em> rule. In this question we see a sequence which follows this rule:

n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}      (1)

Now we prove that given expression contains the pattern:

n = 0

7

n = 1

7 + (- 1)² · 2² = 7 + 4 = 11

n = 2

7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2

n = 3

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18

n = 4

7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7

The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula n = 7 + \sum \limits_{i= 1}^{n} (-1)^{i+1}\cdot (i + 1)^{2}, equivalent to the <em>recurrence</em> formula a_{n+1} = a_{n} + (-1)^{i+1}\cdot (i + 1)^{2}.

To learn more on patterns: brainly.com/question/23136125

#SPJ1

8 0
2 years ago
 
Sav [38]
You lost $30 after everything
5 0
3 years ago
Read 2 more answers
Please help I need just 4 Correct for answers to pass
zlopas [31]

Answer:

Hey!

Your answer is 14m (2sf)

Step-by-step explanation:

<u>WE HAVE TO USE PYTHAGORAS!</u> ⇒ a²+b²=c² THEN √c = (unknown side)

Here: 12² + 8²= 208

Now SQUARE-ROOT 208! ⇒ √208

ANSWER: 14.42220510185596

The answers there are rounded up so we round this number to get 14m!

B IS YOUR OPTION!

<h2><u></u></h2><h2><u>I HOPE THIS HELPED YOU!</u></h2>
5 0
3 years ago
What is the solution set of the system of equations x+y=5 and y=x^2-25
riadik2000 [5.3K]
The solution set is basically when are they equal. to figure this out we must set them equal. So so we will move some stuff around

x+y=5
y=5-x

y=x^2-25

we know that when they are equal their x and y values are equal. So so we know that their y values are the same so we can say:

y=y

this does not direarly help but looking above we know what both of the y's equal. so:

5-x = x^2-25

we want to set this equal to zero

0 = x^2 +x - 30

now we factor

0 = (x + 6) * (x - 5)

the only way to multiply 2 things together and get zero is for one of those things to equal 0. So so we know that to be zero one of the answers in parenthesis has to equal 0. so:

0 = (x + 6 =0) * (x - 5=0)

So now we solve for both parenthesis

x+6=0
x=-6

x-5=0
x=5

x=-6,5
6 0
4 years ago
GIVING BRANIEST FOR #5
Flura [38]

Answer:

we need to see the other page or we cant solve it

Step-by-step explanation:

6 0
3 years ago
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