Question

7) The principal at a high school is planning a concert to raise money for the music programs. He determines

Answer 1

Answer: 6, 45 $

Step-by-step explanation:

$\displaystyle -200t^2+3600t-6400=8500 \ \ |\div100\\\\ -2t^2+36t-64-85 =0 \ \ |\cdot (-1) \\\\ 2t^2-36t+149=0 \\\\ \rm D=36^2-4\cdot2\cdot 149=104 \\\\ x_1=\frac{36+2\sqrt{26} }{4} \approx11,54 \\\\\\ x_2=\frac{36-2\sqrt{26} }{4} \approx 6,45 \\\\ x_2$

Answer 2

Answer:

The smallest amout that the school should charge is $4.70.

Step-by-step explanation:

p = -200t2 + 3600t - 6400

p = -200 x 4.7 x 2 + 3600 x 4.7 - 6400

p = -1880 + 16920 - 6400

p = 15120 - 6400

p = 8720