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Elenna [48]
3 years ago
9

D) - 15/3 = x + 1 how do i solve this

Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:

x = - 6

Step-by-step explanation:

- 15/3 = x + 1

- x = 1 + 15/3

- x = 3/3 + 15/3

- x = 18/3

x = - 18/3

x = - 6

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If x-y=√3, x²-y²=√5 & a²-a√3+1=0, then find out the value of x+y
Lemur [1.5K]

Answer:

√15/3

Step-by-step explanation:

x² - y² =√5

(x +y)*(x -y) = √5

(x +y) * √3 = √5

x+y  = √5 / √3

x +y = √5*√3 / √3*√3

x +y = √15/3

4 0
2 years ago
I need help on this question
Over [174]

1 bushel = 186 heads of lettuces

multiply each side by 6

6 bushels = 1,116 heads of lettuces

The farmer picked 1,116 heads of lettuces

3 0
3 years ago
If x = 5 cm, y = 12 cm, and z = 13 cm, what is the surface area of the geometric shape formed by this net?
Lera25 [3.4K]

Answer:

the answer is C.  210 sq. cm

Step-by-step explanation:

Find the area of the triangle

The area of one of the triangular faces can be found by using the formula below.  

a = 1/2 bh

a = 1/2 (5 cm) (12 cm)

a = 30 sq. cm

Since there are two triangular faces, multiply the area of one triangular face by 2. The area of two triangular faces is 60 cm2.

Next, find the area of each of the three rectangular faces using the formula, area = lw.

1st rectangle

a = lw

a =  (5 cm) (5 cm)

a = 25 sq. cm

2nd rectangle

a = lw

a = (5 cm) (12 cm)

a = 60 sq. cm

3rd rectangle

a = lw

a = (5 cm) (13 cm)

a - 65 sq. cm

Add the three rectangle areas to find a total of 150 sq. cm.

To find the surface area of the triangular prism, add the area of the two triangular faces to the area of the three rectangular faces.

60 sq. cm + 150 sq. cm = 210 sq. cm

4 0
3 years ago
Can someone please answer. There is one problem. There's s picture. Thank you!
Pepsi [2]
The correct answer is the first option, 23.1 miles.

Knowing that the sum of the triangle's interior angles should equal a measure of 180°, you can start off by solving for the missing interior angle, near the library.

Since this is a right triangle (meaning one of the angles is 90°), and the other angle is given (57°), simply subtract these two values from 180° to get 180-(57+90)=33\textdegree.

Next, use the Law of Sines (stated below) which will allow you to solve for the missing distance from the radio tower to the library in miles, using the angle measures and height from the tower to the balloon that you've found.

\frac{\sin(A)}{a} =  \frac{\sin(B)}{b}

For this problem, we'll let the height of the hot air balloon be a=15 and its respective opposite angle be A=33\textdegree, and let the missing x-distance be b, with its respective opposite angle B=57\textdegree. Note, we're solving for b.

\frac{\sin(33)}{15} =  \frac{\sin(57)}{b} \\ \\
b\times sin(33)=15\times \sin(57) \\ \\
b=\frac{15\times \sin(57)}{sin(33)} \\ \\
b\approx \frac{15\times 0.84}{.54} \\ \\
b\approx \frac{12.6}{.54} \\ \\
b\approx \frac{12.6}{.54} \\ \\
b\approx 23.3

Because there was a lot of approximation in the above operations, the answer doesn't exactly match any of the answer options in the question. However, it's very close to the first option, 23.1 miles, so that must be the correct answer.
8 0
3 years ago
Our pool is twice as long as it is wide and is surrounded by a walkway of uniform width of 1 foot. The
Zigmanuir [339]

Step-by-step explanation:

x=width of pool

2x=length of pool

the dimensions of the rectangle forming the walkway and the pool are x+4 and 2x+4

the area of this rectangle minus the area of the pool is 196 square feet

(2x+4)(x+4)-(x)(2x)=196

2x^2+4x+8x+16-2x^2=196

combine similar terms

12x+16=196

12x=196-16

12x=180

x=180/12

x=15 feet is the width of the pool

check: 34*19-30*15=196

646-450=196

196=196

8 0
3 years ago
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