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3 years ago

Solids

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

Answer:

xd? you look like the school hacker

Step-by-step explanation:

Id k

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Find the values of A and B. The diagram is not drawn to scale.

Montano1993 [528]

A = 180 - 36 = 144

b = 360 - (113 + 36 + 144)
b = 60 -293
b = 67

8 0

3 years ago

Read 2 more answers

Chelsea uses 3 pounds of apples to make 4 cups. How many pounds of apple does she need to make 6 pints of applesauce

Gemiola [76]

Here, we know that 1 pint = 2 cups

Thus, 1 cup = $\frac{1 pints}{2}$

3 ponds apples are needed for 4 cups i.e. 3 ponds of apples = 4 cups of applesauce

1 cup of applesauce = $\frac{3 ponds}{4}$

Now, 6 pints will have 12 cups of applesauce

Multiplying this equation by 12 ⇒ 1 cup of applesauce = $\frac{3 ponds}{4}$

12 ×1 cup of applesauce = 12 × $\frac{3 ponds}{4}$

So, 12 cups of applesauce = 9 ponds of apple.

<u>Thus, 9 ponds of apple will be needed to make 6 pints of applesauce.</u>

7 0

3 years ago

Read 2 more answers

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

Work out the angle of x

Amiraneli [1.4K]

Answer:

Cos60=1/2=0.5

cos60=4/x

0.5=4/x

0.5x=4

0.5x/0.5=4/0.5

x=8

3 0

3 years ago

a piece of wood used for construction is 2 inches by 4 inches by 24 inches. what is the surface area of the wood

FrozenT [24]

2*2*4+2*2*24+2*4*24
16+96+192=304

304 is the answer

8 0

3 years ago