Answer:
Check pdf
Step-by-step explanation:
Answer:
- asymptotes: x = -4, x = 4
- zeros: x = 0
Step-by-step explanation:
The vertical asymptotes of the rational expression are the places where the denominator is zero:
x^2 -16 = 0
(x -4)(x +4) = 0 . . . . . true for x=4, x=-4
x = 4, x = -4 are the equations of the vertical asymptotes
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The zeros of a rational expression are the places where the numerator is zero:
4x = 0
x = 0 . . . . . . divide by 4
1) 4x + 3(x-9) = 19
or, 4x + 3x - 27 = 19
or, 7x = 19+27
or, 7x = 46
or, x = 46/7
◆ x = 6.57
2) 2(x-4) + 5x = 3
or, 2x - 8 + 5x = 3
or, 7x = 3+8
or, x = 11/7
◆ x = 1.57
3) 60 = 8y - 3(y-10)
or, 60 = 8y - 3y + 30
or, 60 - 30 = 5y
or, y = 30/5
◆ y = 6
4) 40 + 3c = 3 + 9(c-2)
or, 40 + 3c = 3 + 9c - 18
or, 40 + 3c = 9c - 15
or, 9c - 3c = 40 + 15
or, 6c = 55
◆ c = 9.166
I hope you understand..
Thank you...♥♥
Answer:
Step-by-step explanation:
Answer:
0.49
Step-by-step explanation:
We apply conditional probability to solve this question.
We have Events X and Events Y
P(X) = Probability Christine fails the course = ??? Unknown
P(Y) = Probability Christine finds a tutor
= 0.35
P(Y') = Probability Christine does not find a tutor = 1 - 0.35 = 0.75
P(X|Y) = Decrease in her probability of failing = 0.35
P(X|Y') = Probability that she will fail the course if she does not have a tutor
P(X) = P(X|Y) × P(Y) + P(X|Y') × P(Y')
P(X) = 0.35 × 0.75 + 0.65 × 0.35
P(X) = 0.2625 + 0.2275
P(X) = 0.49
The probability that Christine fails the course is 0.49
