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2 years ago

A line passes through the point (-6,9) and has a slope of 3/2. Write an equation in slope-intercept form for this line.

Mathematics

1 answer:

BaLLatris [955]2 years ago

7 0

Answer:

y=3/2x+18

Step-by-step explanation:

Hi there!

We are given a point (-6,9) and a slope of 3/2

We want to write the equation of this line in slope-intercept form

Slope-intercept form is written as y=mx+b, where m is the slope and b is the y intercept

Since we already know the slope of the line as 3/2, we can substitute it as m into the equation:

y=3/2x+b

Now let's find b

Since the equation of the line passes through (-6,9), we can use it to help solve for b

Substitute -6 as x and 9 as y:

9=3/2(-6)+b

Multiply

9=-9+b

Add 9 to both sides

18=b

Substitute 18 as b into the equation.

y=3/2x+18

Hope this helps!

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Answer:

The plane's distance from the radar station will increase about 8 miles per minute when it is 5 miles away from it.

Step-by-step explanation:

When the plane passes over the radar station, the current distance is the altitude h = 2. Then it moves b horizontally so that the distance to the station is 5. We can form a rectangle triangle using b, h and the hypotenuse 5. Therefore, b should satisfy

h²+b² = 5², since h = 2, h² = 4, as a result

b² = 25-4 = 21, thus

b = √21.

Since it moved √21 mi, then the time passed is √21/540 = 0.008466 hours, which is 0.51 minutes. Note that in 1 minute, the plane makes 540/60 = 9 miles.

The distance between the plane and the radar station after x minutes from the moment that the plane passes over it is given by the function

$f(x) = \sqrt{((9x)^2 + 2^2)} = \sqrt{(81x^2+4)}$

We have to compute the derivate of f in x = 0.51. The derivate of f is given by

$f'(x) = \frac{162x}{2\sqrt{81x^2+4}}$

also,

$f'(0.51) = \frac{162*0.51}{2\sqrt{81*0.51^2+4}} = 8.2486$

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