Answer:

Step-by-step explanation:
We are given that
Equation of curves


Both curves lie on S.
We have to find the equation of tangent plane at P(4,1,4).


Hence, t=0 and u then it satisfied the given point.
Substitute the values in the derivatives


The equation of tangent at point P(4,1,4) is given by




Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0) - Parallel lines always have the same slope
<u>1) Determine the slope (m)</u>

In the given equation,
is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of
. Plug this into
:

<u>2) Determine the y-intercept (b)</u>

Plug in the given point (-6,-29) and solve for b

Simplify -6 and 2

Add 15 to both sides to isolate b

Therefore, the y-intercept is -14. Plug this back into
:

I hope this helps!

Subtract 10 from both sides.

Since the square of a number, x, equals a negative number, -1, the answer cannot be a real number because the square of a real number is always non-negative. Therefore, there is no real number solution to this equation.
Answer: <span>B. no real number solutions</span>
B
Hope this helps :)
Can I have Brainliest please
Answer:
y= 4x^2
Step-by-step explanation: