Answer:
i dont know
Step-by-step explanation:
hynmk,likujnyhbgfd
(4+3)(7-4) if you want the products to multiply each other
4+3(7-4) if you want to use the distributive property and simply have 3 multiplied but the simplification of 7-4 which is 3
Answer: m = 0
Step-by-step explanation:
Answer:
Number of bulbs which can be lit using 1 kg of coal = 9
Step-by-step explanation:
Energy yielded by burning 1 kg of coal = 30 × 106 joules
= 3180 joules
Amount of energy that can be used for electricity = 30 % of 3180 joules
= 0.30 × 3180
= 954 joules
Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting
⇒ Energy needed for lighting one bulb = 100 × 1
= 100 joules

Hence, Number of bulbs which can be lit using 1 kg of coal = 9