Question

What is the slope-intercept form of an equation of a line that passes through the point (0,-1) and is perpendicular to 5x-y=3?

Answer 1

Answer:

y = -1/5x - 1

Step-by-step explanation:

Perpendicular lines slopes are negative reciprocals of each other.

Write the given equation in the slope-intercept form: y = mx + b

5x - y = 3

-y = -5x + 3

y = 5x - 3       multiply by -1

The slope of the given line is 5 ( the coefficient of the x-term).

The slope of the new equation will -1/5 (this is the negative reciprocal of 5).

Next find "b"  using y = mx + b, the new slope -1/5 and the point (0, -1)

y = mx + b

-1 = -1/5(0) + b

-1 = 0 + b

-1 = b  

Now write the equation y = -1/5x - 1