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blsea [12.9K]
2 years ago
14

Density is the ratio of mass to volume.

Mathematics
1 answer:
Nikitich [7]2 years ago
6 0

Answer:

the greatest density is glycerin

the least density is olive oil  

Step-by-step explanation:

i hope you get ahead in your assignments! good luck!:)

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What is 2 times 3? Im just asking a dumb question so u can get points
Kazeer [188]

Answer:

The answer is Six

Step-by-step explanation:

2+2+2 3 times is 6

5 0
4 years ago
15. Find the value of x and y rounded to the nearest tenth.<br> X<br> 34<br> 45°<br> 30°<br> y
Ugo [173]

Answer:

x = 24.0

y = 46.4

Step-by-step explanation:

Let opposite side = z

Using trigonometry :

Sin 30 = z / 34

z = 0.5 * 34

z = 17

We find x :

Sin 45 = 17 / x

x * sin45 = 17

x = 17 / sin 45

x = 24.04

Let y = y1 + y2

y1 = 17 / tan45

y1 = 17

y2 = 17/tan30

y2 = 29.44

y = 17 + 29.44

y = 46.44

6 0
3 years ago
Plzzzzzzz helpppppppppppppp
Katarina [22]

Answer:

144

Step-by-step explanation:

i think if i am wrong dont judge

6 0
4 years ago
Evaluate the expression. Will choose brainliest
svet-max [94.6K]

Answer:

-213

Step-by-step explanation:

3|3-5|^2-(-15)^2

3(4)-225

=12-225= -213

3 0
3 years ago
Read 2 more answers
A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its
VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate (\dot V), measured in liters per hour, is directly proportional to draining time (t), measured in hours. That is:

\dot V \propto \frac{1}{t}

\dot V = \frac{k}{t} (Eq. 1)

Where k is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

\dot V_{s}+\dot V_{l} = \frac{k}{2} (Eq. 2)

\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}

(ii) <em>Only the small drain is opened</em>

\dot V_{s} = \frac{k}{t_{l}+3} (Eq. 3)

\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}

(iii) <em>Only the big drain is opened</em>

\dot V_{l} = \frac{k}{t_{l}} (Eq. 4)

\frac{\dot V_{l}}{k}  = \frac{1}{t_{l}}

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}

\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}

2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}

t_{l}^{2}-t_{l}-3 = 0 (Eq. 5)

Whose roots are determined by the Quadratic Formula:

t_{l,1}\approx 2.303\,h and t_{l,2} \approx -1.302\,h

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

t_{s} = 2.303\,h+3\,h

t_{s} = 5.303\,h

The draining time when only the small drain is opened is 5.303 hours.

7 0
3 years ago
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