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Jet001 [13]
3 years ago
13

What is the answer to s/3-7/6+2s/5=3s/4 s= -----

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

s  = -70 in the given expression.

Step-by-step explanation:

Here, the given expression is:

\frac{s}{3} - \frac{7}{6} + \frac{2s}{5} = \frac{3s}{4}

Now, to find the value of s, we need to simplify the given expression:

We get:

\frac{s}{3} - \frac{7}{6} + \frac{2s}{5} = \frac{3s}{4}\\\implies \frac{s}{3}  + \frac{2s}{5} -  \frac{3s}{4}  = \frac{7}{6}\\\implies\frac{20(s) + 12(2s) - 15(3s)}{60}    = \frac{7}{6}\\\implies \frac{20 s  + 24 s - 45 s}{60}   = \frac{7}{6}\\\implies \frac{-s}{60} = \frac{7}{6}\\\implies s = \frac{7}{6} \times (-60)  = - 70\\\implies s  = (- 70)

Hence, s  = -70 in the given above expression.

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Determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor
Nesterboy [21]

Answer:

$64, \ (x+8)^2$

Step-by-step explanation:

A perfect square trinomial is defined as an expression that is obtained from squaring a binomial equation. The perfect square trinomial is in the form of $ax^2+bx+c$.

The given expression is :

$x^2+16x$

The co-efficient of the x-term in $x^2+16x$ is '16'.

So half of the term 16 ,

$\frac{16}{2} = 8$

and $(8)^2=64$

Now add 64 to the expression:

$x^2+16x+64$

Therefore, the perfect square trinomial is

$(x+8)^2=x^2+16x+64$

8 0
3 years ago
X^2+x-6 plz tell this
kramer

Answer:

The answer will be -12 because you are multiplying 2x and -6

4 0
3 years ago
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2n is greater than 14
nataly862011 [7]
The answer is    n > 7.  This is the answer
6 0
4 years ago
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How to find vertical and horizontal asymptotes of polynomials?
guajiro [1.7K]
Vertical asymptotes are when y tends to infinity, which in other words means you need a fraction where you're dividing by zero. So to find the vertical asymptotes, solve the denominator of the fraction and the solutions are the asymptotes since that is where it will be dividing by zero.

Horizontal asymptotes are the opposite and is where x tends to infinity -- This can be done by dividing through with the xs still there, since you are effectively just looking at multiples of infinity and infinity squared and so on. When you have an x to the power you can forget about all the other x's on the same half of the fraction, since infinity squared is infinitely bigger than infinity - yes it's abstract and a bit stupid I know.
If the degree of the polynomial on the denominator is larger than the numerator, there is an asymptote at y=0 (since the bottom becomes infinitely larger than the top). If it is lower than the numerator, you have to divide through by long division and you end up with an oblique asymptote i.e. an asymptote where the dotted line would follow a linear equation e.g. y=x

For example
f(x)= \frac{6x^2-3x+4}{2x^2-8}

The vertical asymptote can be found by solving 2x^2-8=0 i.e. x=+-2 so our vertical asymptotes are at 2 and -2.

The horizontal asymptote, think of all the x's as infinity. SInce there are x^2s, we dont need to worry about the numbers or the other x's
Therefore we are left with 6x^2/2x^2, which gives us 3. Therefore our horizontal asymptote would be at y=3.
7 0
3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER PLEASE
iren [92.7K]

Answer:

1st answer was wrong

area of circle - quarter

Step-by-step

100pi- (100pi÷4)

100pi - 25pi

75pi

5 0
2 years ago
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