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Ivahew [28]
3 years ago
14

What is differentiation ?

Mathematics
2 answers:
Shtirlitz [24]3 years ago
4 0

Answer:

In mathematics, the derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument. Derivatives are a fundamental tool of calculus.

deff fn [24]3 years ago
3 0
The derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument. Derivatives are a fundamental tool of calculus


(Sorry if this didn’t help)
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You purchased an investment for $5000 that gains 11% in value every year.
german

Answer:

After 20 years the investment will be worth 11,000$

Step-by-step explanation:

in order to solve the problem you have to turn the percent into a decimal by moving the percent sign twice to the left. which will result in ".11"

then you multiply 5,000x.11 and it equals to 550 per year.

multiply 550x20 and you get 11,000

if I'm not correct please tell me the right answer! goodluck!

3 0
4 years ago
Read 2 more answers
What equation describes the same line as y-6 = -4 (x+1)
olga55 [171]

Answer: y=-4x+2

Step-by-step explanation: Move all terms not containing Y to the right side of the equation.

3 0
3 years ago
Find the volume of the cone.
zhenek [66]

The volume of the cone of  radius 5 units and height 3 units is 78 cubic units.

Given radius of cone 5 units and height of cone be 3 units.

We are required to find the volume of cone.

Volume is the amount of substance that a container can hold in its capacity.

Formula of cone is 1/3 *πr^{2} h in which  r is radius and h is height of cone.

We have to just put the values in formula.

Volume=1/3 *π5^{2} 3

=25*3π/3

=75π/3

=25π

Put π=3.14 as said in the question.

=25*3.14

=78.5 cubic units.

After rounding we will get 78.

Hence the volume of cone whose radius is 5 units and height is 3 units is to be 78 cubic units.

Learn more about volume at brainly.com/question/463363

#SPJ4

Question is incomplete as it should include the figure.

5 0
2 years ago
Equation for a circle with a diameter that has endpoints at (2, –5) and (8, –9)
chubhunter [2.5K]

The standard form for the equation of a circle is :

<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :

 ((2+(8))/2,(-5+(-9))/2)=(5,-7)

 So the point (5,-7) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(2−(5))^2+(-5−(-7))^2=9+4=13

 ⇒r=√13

 Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :

 (x-5)^2+(y+7)^2=13

5 0
4 years ago
The given line passes through the points (0, −3) and (2, 3).
Alex

Answer:

The equation would be y + 1 = 3(x + 1)

Step-by-step explanation:

In order to find the equation of this line, we have to use the slope formula to find the slope.

m (slope) = (y2 - y1)/(x2 - x1)

m = (3 - -3)/(2 - 0)

m = (3 + 3)/(2 - 0)

m = 6/2

m = 3

Now that we have that, we can use it along with the second point to put into the point-slope equation.

y - y1 = m(x - x1)

y - -1= 3(x - -1)

y + 1 = 3(x + 1)

6 0
4 years ago
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