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lapo4ka [179]
3 years ago
11

Find Lateral Surface area

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

To find the lateral surface area, we will find half of the perimeter of the base and multiply it by the slant height of the side triangles. Each triangle has a slant height. The slant height is the height of each triangle, not the height of the pyramid.

Step-by-step explanation:

Lelechka [254]3 years ago
4 0

Answer:

Step-by-step explanation:

The area of all the sides of the object excluding the area of its base and top

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(3m±4/5n)2<br>solve this question<br>​
sukhopar [10]

Answer:

(3m-4/5)2  

Final result :

 (15m - 4)2

 ——————————

     52    

Step by step solution :

Step  1  :

           4

Simplify   —

           5

Equation at the end of step  1  :

        4

 (3m -  —)2

        5

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

          3m     3m • 5

    3m =  ——  =  ——————

          1        5    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3m • 5 - (4)     15m - 4

————————————  =  ———————

     5              5    

Equation at the end of step  2  :

 (15m - 4)

(—————————)2

     5    

Step  3  :

Final result :

 (15m - 4)2

 ———

     52    

Step-by-step explanation:

5 0
2 years ago
Evaluate 2b^2 − 4a + 4a^2 for a = 3 and b = −8.
kipiarov [429]

(2*(-8)^2)-(4*3)+(4*3^2)

128-12+36

152

6 0
2 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
Write a verbal description for each algebraic expression 100-5n
Reika [66]

Step-by-step explanation:

One hundred minus five n

6 0
3 years ago
What’s the correct answer
Trava [24]
I think it’s B but I’m not sure
6 0
3 years ago
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