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2 years ago

Write an equation for this linear function. f(0)=3 and f(3)=0 f(x)=

Mathematics

1 answer:

Jlenok [28]2 years ago

5 0

Answer:

f(x)=-x+3

Step-by-step explanation:

contains (0, 3) and (3, 0)

slope = (3-0)/(0-3)=3/-3=-1

f(x)=-x+b

b=3

f(x)=-x+3

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Triangle E D F has sides that are of varying lengths. Side E D has a length of 4 and side E F has a length of 9.

9966 [12]

Answer:

D E + E F greater-than D F

5 less-than D F less-than 13

Triangle D E F is a scalene triangle

Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

we have the triangle EDF

where

$ED=4\ units\\EF=9\ units$

<u><em>Applying the triangle inequality theorem</em></u>

$ED+EF > DF\\4+9 > DF\\13 > DF\\DF < 13\ units$

$ED+DF > EF\\4+DF > 9\\DF > 5\ units$

The length of DF is the interval -----> (5,13)

The triangle DEF is a scalene triangle (the three length sides are different)

therefore

<em>The statements that are true are</em>

D E + E F greater-than D F

5 less-than D F less-than 13

Triangle D E F is a scalene triangle

3 0

3 years ago

Read 2 more answers

A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

3 0

3 years ago

Read 2 more answers

From the airport hanger H, an areoplane A is 18km away on the bearing of 115° while another aeroplane B is 29km away on a bearin

maks197457 [2]

The difference in distance between Aero plane A and B is; 34.67 km

<h3>How to calculate bearing?</h3>

To get the bearing;

∠H = (115 - 90) + (270 - 203)

∠H = 92°

Then, we will use cosine rule to get the distance between both Planes A and B.

d_ab = √(18² + 29² - 2(18 * 29) * cos 92)

d_ab = √(324 + 841 + 36.435)

d_ab = 34.67 km

Read more about bearing at; brainly.com/question/22518031

#SPJ1

6 0

2 years ago

Mr. O'Connor had $90 to spend at a football game. He spent 31/45 on his ticket. Then, he spent 3/7 of his remaining money at the

Kobotan [32]

He has $90 in total to spend

He spent (31/45) of this money on ticket

so money spent on ticket =(31/45) *90 =2790/45 =62

Now money left with him is 90-62 =28 $

Now it says that he spent (3/7) of this remaining money at concession stand

so money spent on concession stand =(3/7)*28 =84/7 =12

Now money left with him = 28-12 =16

So money left with him is $16 but hat costs for $18

So Mr. O'Connor didnt have enough moeny to buy the hat

4 0

3 years ago

I need some DETAILED examples of Dividing Integers! Urgent, pls help ASAP!

vfiekz [6]

Here are some examples:

Integers are positive and negative numbers, but dividing integers are dividing positive and negative numbers:

Remember these rules:

Negative divided by a negative equals a positive.
Negative divided by a positive equals a negative.
Positive divided by a positive equals a positive .

Examples:

$-4 \div 2 = -2$
$-4 \div -4 = 1$
$4 \div 2 = 2$

Hope this helps!

8 0

3 years ago