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3 years ago

5

Sorry for the spam, I just really need help.

1 answer:

zloy xaker [14]3 years ago

3 0

13 is C and 14 is b

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The cross country team practice by jogging on town steerts the average jogging rate is 6 mile per hour one member jogged for 3.5

seropon [69]

Answer:

6mile + hour + 3.5 hours + miles

Step-by-step explanation:

add the expressions

8 0

3 years ago

How do you solve these problems without numbers

insens350 [35]

i dont know if you want me to answer them or not, but you have to COMBINE LIKE TERMS if you dont then your problems would be messed up example if you have a+a it would be 2a make sense? so you want everything combined then you have to solve. theres no possible way of solving these without numbers number would have to be added although youll probably end up getting rid of the numbers in the end. after you combine like terms do the rest of solving

hope that helps if you need more help pm me, :)

7 0

3 years ago

Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr

Fed [463]

Answer:

There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

Given

Let subscript 1 represent men and 2 represent women, respectively.

$n_1 = 25$

$n_2 = 21$

$s_1 = 0.98$

$s_2 = 1.02$

$\alpha = 0.02$

Required

Determine if here is enough evidence

First, we need to state the hypotheses

$H_o: \sigma_1^2 = \sigma_2^2$

$H_1: \sigma_1^2 \ne \sigma_2^2$

Next, calculate the test statistic using:

$F = \frac{s_1^2}{s_2^2}$

$F = \frac{0.98^2}{1.02^2}$

$F = 0.923$

Calculate the rejection region;

But first, calculate the degrees of freedom

$df_1 =n_1 - 1$

$df_1 =25 - 1$

$df_1 =24$

$df_2 = n_2 -1$

$df_2 = 21 - 1$

$df_2 = 20$

Using the F Distribution: table

$c = \frac{\alpha}{2}$

$c = \frac{0.02}{2}$

$c = 0.01$

At 0.01 level (check row 20 and column 24), the critical value is:

<em></em> $f_{0.01,24,20} = 2.86$ <em> --- the upper bound</em>

At 0.01 level (check row 24 and column 20), the critical value is:

$f_{0.01,20,24} = 2.74$

Calculate the inverse F distribution.

$f_{0.99,20,24} = \frac{1}{f_{0.01,20,24}} = \frac{1}{2.74} =0.365$ ---- the lower bound

The rejection region is then represented as:

$0.365 < Test\ Statistic < 2.86$

If the test statistic falls within this region, then the null hypothesis is rejected

$F = 0.923$ --- Test Statistic

$0.365 < 0.923 < 2.86$

<em>The above inequality is true; so, the null hypothesis is rejected.</em>

<em>This implies that, there is no sufficient evidence.</em>

7 0

3 years ago

HELP PLEASE ILL GIVE YOU 15 POINTS THANK YOU

sasho [114]

Answer:

X Y

4. 2

8. 3

12. 4

hope this is helpful for you

8 0

3 years ago

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I would like to buy a sandwich and pancakes, which would be $8.50, with a 6% tax and 20% gratuity, how much would that be all in

Luda [366]

Answer:

9.01 maybe my math might be wrong

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers