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svet-max [94.6K]

3 years ago

12

a scale drawing of an automobile has a scale of 1 inch= 1/2 foot. The actual width of the car is 8 feet. What is the width on th

e scale drawing?

1 answer:

Trava [24]3 years ago

7 0

Answer:

16 inches

Step-by-step explanation:

8 x 2 = 16

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Its an acute triangle by angles.

Its a NONE by sides.

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3 years ago

18% of what number is 29?

galina1969 [7]

Alright, so we are trying to figure out what number 18% of equals 29. First, we should divide 100 by 18 we get 5.55555555555. That means 29*5.5555555555 is the number we are looking for: <em>29*5.5555555555=161.111111</em>

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4 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

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With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

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3 years ago

Need help with this.

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I can’t see your question I wish I could help you

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3 years ago

Five less than four times a number is nine more than twice a number

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5-4a=9+2a
Hope this help

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3 years ago

Read 2 more answers