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grandymaker [24]
3 years ago
9

Which number is a zero of the given function? g(x) = (x^2– 36) (x + 7)

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0
You can factor it more
Remember: (a^2 - b^2) = (a-b)(a+b)
(x^2 - 36) = (x - 6)(x + 6)
Now plug back to equation

(x - 6)(x + 6)(x + 7) = 0
x - 6 = 0, x = 6
x + 6 = 0, x = -6
x + 7 = 0, x = -7

Solution: x = 6, -6, -7
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