Point Form: (1,-5)
Equation Form: x-1,y=-5
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.
Answer:
A
Step-by-step explanation:
I'm not sure but I think it's A
hope this helps : )
200,000,000+8,000,000+400+70+8=208,000,478
Answer:
Option E
Step-by-step explanation:
The standard equation of circle is:- (x-h)² + (y-k)² = r²
where (h,k) is center point and r is radius
If radius r is decreased then also (h,k) remains same, only r² increases
Equation given in question is x² + y² + Cx + Dx + E=0
So, C and D will remain same but E will increase